Re: [理工] 一階正合ODE

作者: Honor1984 (希望願望成真)   2017-11-20 16:58:24
※ 引述《wadeinthe (周偉德)》之銘言:
: 積分做起來卡卡的,不知有沒有高手肯出手相救
: https://i.imgur.com/LNJrnQP.jpg
: 計算過程有誤嗎?
(d/dx)sec(x + y^2) + [d/d(x + y^2)]sec(x + y^2) * [(d/dx)(x + y^2) - 1]
+ sqrt(y)dy/dx = 0
=> (d/dx)sec(x + y^2) + (d/x)(2/3)y^(3/2) = 0
=> sec(x + y^2) + (2/3)y^(3/2) = c
作者: wadeinthe (周偉德)   2017-11-20 17:11:00
答案跟我一樣,請問計算有錯嗎?尤其是sec tan 那個積分

Links booklink

Contact Us: admin [ a t ] ucptt.com