[問題] 數獨又卡關了

作者: gerychen (邪惡肥宅)   2020-08-02 10:10:53
https://i.imgur.com/YHGiBwE.jpg
反覆重解了幾次
還是卡在一樣的地方
求推解:(
作者: EIORU   2020-08-02 22:43:00
1. C1R678/C6R67/C9R78 HAS 6, C234R678 NO 62. C1R4 C3R6 HAS 39, C3R4=5
作者: funkie (乾!!草泥馬)   2020-08-02 23:52:00
1. 考慮R1和R8的4, R1C3(4,6)=>R8C2(4,5,6)不能是6。因為會變成非唯一解2. R1C3(4,6),R8C2(4,5) and R9C3(5,6)=>R1C3=4 or R8C2=4 => R8C3 不是 4

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