這題跟前一題條件有關 assume that transactions mayrequires 5 I/O operations另外 最後一行 arrive at the beginning of a 1-sec我覺得這個地方應該是 100us9 transcation * 5 * 20 ms + 100us + 10th transcat阿 我知道了 抱歉 是100ms 沒錯 我另外打一篇仔細想想是應該還是100us QQtions = 9*5*20ms + 100us + 1*5*20ms = 1.0001sB: 9*5*18ms+ 100us = 810.1ms < 1s∴加上下輪10 transaction 1th and 2th=990.1ms <1s更正 10th 11th transaction