Re: [問題] SQL count 的替代方法

作者: cspy (Perfect Stranger)   2010-10-20 11:36:50
select
*
from
(select *,count(name) as number from tt group by name) as x
where
x.age > 20 and x.number = 2 and car_id <> '';
※ 引述《dayyoung (dayyoung)》之銘言:
: NAME AGE CAR_ID
:
作者: zainan (宅男)   0000-00-00 00:00:00

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